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React Native - How to Application X open Application Y if Application Y has been installed

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I want My Application (say Application X) want to open Application Y, if Application Y installed. And work in Android and iOS (open App Store / Play store if Application Y not installed)

What i have done :

Linking.openURL(applicationStoreURL);

The code above success open Play Store/App Store of Application Y, but actually the application Y has been installed so i want to direct open to Application Y from Application X.


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