I want to open New React native App by clicking on Button in which I have used
Linking Concepts in React native
React native Code : Test is the name of the Other App
Linking.openURL('Test://app');
Also Following URL for adding Intent in the android.manifest.xml file Andriod Intent
Code : Android.manifestfile.xml
<activity
android:name=".MainActivity"
android:launchMode="singleTask"
android:label="@string/app_name"
android:configChanges="keyboard|keyboardHidden|orientation|screenSize"
android:windowSoftInputMode="adjustResize">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="com.Test" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="Test" android:host="app" />
</intent-filter>
</activity>
Please help to resolve the issue , thanks in advance!